Kirk Just Kirk
wb6egr at gmail.com
Fri May 10 17:48:45 EDT 2013
Let me explain...the 4049 and 4050 are CMOS "Buffer" chips..one
inverts..the other doesn't. WHY THIS chip? VERY few CMOS device will allow
you to pull a input above the supply rail voltage without literally blowing
the top off the chip....
Stock up now..
On Fri, May 10, 2013 at 11:31 AM, Jim Duuuude <telesistant at hotmail.com>wrote:
> Just a suggestion in general:
> We are ham radio operators. By definition, we have, at least, a certain
> basic knowledge of
> electronics (as is required to pass our test).
> If two devices are somehow electrically incompatible with each other, use
> your knowledge of
> electronics to build a simple circuit to interface them together.
> Converting from one set of
> "levels" to another is REALLY not that difficult.
> That's why we are what we are, and do what we do.
> Jim WB6NIL
> P.S. Or, you can use pin 8 *LIKE EVERY ONE ELSE DOES*!!
> > From: n5zua at earthlink.net
> > To: app_rpt-users at ohnosec.org
> > Date: Fri, 10 May 2013 16:14:00 -0500
> > Subject: Re: [App_rpt-users] GM300
> > <http://www.batlabs.com/images/gmacc8.gif>
> > Gotcha. Not sure if you mentioned if yours was a 16 channel or not. If
> an 8
> > channel, the above link lists pin 4 as a spare, and instructs that pin 8
> > should be used for COR active low. Since you mentioned getting voltage
> > of pin 4, I'm assuming yours is a 16 channel radio. Folks with an 8
> > model would not have the option you are using.
> > N5ZUA
> > ----- Original Message -----
> > From: "Bill Hurlock" <bill.hurlock at cpcomms.com>
> > To: <app_rpt-users at ohnosec.org>
> > Sent: Friday, May 10, 2013 3:54 PM
> > Subject: Re: [App_rpt-users] App_rpt-users Digest, Vol 51, Issue 9
> > > Here is a clip about PIN 4 in the Accessory plug of a GM300.
> > >
> > > 4 Programmable Output Only This is a radio output port. It is an open
> > > collector output which saturates to A+ supply when active. It is
> > > used to drive an external relay or sense lead. It duplicates the
> > > of J3-3 of the five pin logic board. When active it can source a
> > > current of 250 mA.
> > > The pin has a 10 K ohm resistor pull-down to ground on the logic
> > > and uses a PNP transistor to switch it up to 12V. This pin does not
> > > as an active low pin (i.e. pulling something to ground), only as an
> > > high (that is dragging something up to +12v). If you want an active
> > > output to drive a reed relay which has the other side of the coil to
> > > ground, this is your pin (but don't forget to check that the backwards
> > > diode is present on the coil pins).
> > >
> > > Bill Hurlock
> > _______________________________________________
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> > App_rpt-users at ohnosec.org
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